Sum & Count of Even Odd Separately in Array

// Write a C++ program to input 10 numbers
// in array then display sum and count of even
// and odd numbers in Array, separately.
// Author: www.EasyCodeBook.com (c)
#include<iostream>

using namespace std;
int main()
{
	int arr[10],i,esum,osum,ecount,ocount;
	for(i=0;i<10;i++)
	{
		cout<<"Enter Number "<<(i+1)<<"  :";
		cin>>arr[i];
	}
	esum=osum=ecount=ocount=0;
	//show even numbers, sum and count
	cout<<"Even numbers in Array are:"<<endl;
	for (i=0;i<10;i++)
	  if(arr[i]%2==0)
	  {
	  	cout<<arr[i]<<", ";
	  	ecount++;
	  	esum=esum+arr[i];
      }
	cout<<"\nCount of Even numbers is: "<<ecount<<endl;
	cout<<"Sum of Even numbers is: "<<esum<<endl;
	// show even numbers, sum and count
	cout<<"Odd numbers in Array are:"<<endl;
	for (i=0;i<10;i++)
	  if(arr[i]%2==1)
	  {
	  	cout<<arr[i]<<", ";
	  	ocount++;
	  	osum=osum+arr[i];
      }
	cout<<"\nCount of Odd numbers is: "<<ocount<<endl;
	cout<<"Sum of Odd numbers is: "<<osum<<endl;
	
	
	return 0;
}